Penjelasan dengan langkah-langkah:
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[tex]\tt 2022^{x^2 + 2x + 1} = 1[/tex]
[tex]\tt 2022^{x^2 + 2x + 1} = 2022^0[/tex]
[tex]\tt x^2 + 2x + 1 = 0[/tex]
[tex] \tt (x + 1)^2 = 0[/tex]
[tex]\tt x + 1 = 0[/tex]
[tex]\tt x = 0 - 1[/tex]
[tex]\tt x = - 1[/tex]
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[tex]\tt 4^{x^2 + 6x + 8} = 7^{x^2 + 6x + 8}[/tex]
[tex]\tt \dfrac{4^{x^2 + 6x + 8}}{7^{x^2 + 6x + 8}} = \dfrac{7^{x^2 + 6x + 8}}{7^{x^2 + 6x + 8}}[/tex]
[tex]\tt \left(\dfrac{4}{7} \right)^{x^2 + 6x + 8} = 1[/tex]
[tex]\tt \left(\dfrac{4}{7}\right)^{x^2 + 6x + 8} = \left(\dfrac{4}{7}\right)^0[/tex]
[tex]\tt x^2 + 6x + 8 = 0[/tex]
[tex]\tt x^2 + 4x + 2x + 8 = 0[/tex]
[tex]\tt x (x + 4) + 2(x +4) = 0[/tex]
[tex]\tt (x + 4)(x + 2) = 0[/tex]
[tex] \\ [/tex]
[tex]\tt x + 4 = 0[/tex]
[tex]\tt x = 0 - 4[/tex]
[tex]\tt x = - 4[/tex]
[tex] \\ [/tex]
[tex]\tt x + 2 = 0[/tex]
[tex]\tt x = 0 - 2[/tex]
[tex]\tt x = - 2[/tex]
[tex] \\ [/tex]
[tex]\tt x_1 = - 4 \: \: \text{atau} \: \: x_2 = - 2[/tex]
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